hyperbolic function in awk

Since:

sinh(x)=[exp(x)-exp(-x)]/2
cosh(x)=[exp(x)+exp(-x)]/2
tanh(x)=sinh(x)/cosh(x)

Therefore:

/usr/bin/awk '{print (exp($1)-exp(-$1))/2}' in.dat
/usr/bin/awk '{print (exp($1)+exp(-$1))/2}' in.dat
/usr/bin/awk '{print (exp($1)-exp(-$1))/(exp($1)+exp(-$1))}' in.dat

will give sinh, cosh, and tanh for the data inside in.dat.

An example is below, the first column is input, the rest 3 columns are output of sinh, cosh, and tanh using the above awk commands.
-9.0 -4051.5400 4051.5400 -1.0000
-8.0 -1490.4800 1490.4800 -1.0000
-7.0 -548.3160 548.3170 -1.0000
-6.0 -201.7130 201.7160 -1.0000
-5.0 -74.2032 74.2099 -0.9999
-4.0 -27.2899 27.3082 -0.9993
-3.0 -10.0179 10.0677 -0.9951
-1.0 -1.1752 1.5431 -0.7616
-0.6 -0.6367 1.1855 -0.5371
-0.3 -0.3045 1.0453 -0.2913
0.0 0.0000 1.0000 0.0000
0.3 0.3045 1.0453 0.2913
0.6 0.6367 1.1855 0.5371
1.0 1.1752 1.5431 0.7616
2.0 3.6269 3.7622 0.9640
3.0 10.0179 10.0677 0.9951
4.0 27.2899 27.3082 0.9993
5.0 74.2032 74.2099 0.9999
6.0 201.7130 201.7160 1.0000
7.0 548.3160 548.3170 1.0000
8.0 1490.4800 1490.4800 1.0000
9.0 4051.5400 4051.5400 1.0000